The velocity of a particle at an instant is 10 m . After 3 s, its velocity will become 16 m . The velocity (in m ) at 2 s, before the given instant will be

Question

The velocity of a particle at an instant is 10 m $s ⁻ ¹$ . After 3 s, its velocity will become 16 m $s ⁻ ¹$ . The velocity (in m $s ⁻ ¹$ ) at 2 s, before the given instant will be

Smart Achievers · Accepted Answer

(1)

Here, $u = 10 m s^{- 1}$ , $t = 3 s$ , $v = 16 m s^{- 1}$

$a = \frac{v - u}{t} = \frac{16 - 10}{3} = 2 m s^{- 2}$

Now velocity at $2 s$ , before the given instant,

$10 = u' + 2 \times 2$

$∴$ $u' = 6 m s^{- 1}$ $(∵ v = u + a t)$

Solution

Q.
The velocity of a particle at an instant is 10 m $s ⁻ ¹$ . After 3 s, its velocity will become 16 m $s ⁻ ¹$ . The velocity (in m $s ⁻ ¹$ ) at 2 s, before the given instant will be

1 6

2 4

3 2

4 1

Ans.
(1)

Here, $u = 10 m s^{- 1}$ , $t = 3 s$ , $v = 16 m s^{- 1}$

$a = \frac{v - u}{t} = \frac{16 - 10}{3} = 2 m s^{- 2}$

Now velocity at $2 s$ , before the given instant,

$10 = u' + 2 \times 2$

$∴$ $u' = 6 m s^{- 1}$ $(∵ v = u + a t)$

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Solution

Q. The velocity of a particle at an instant is 10 m s⁻¹. After 3 s, its velocity will become 16 m s⁻¹. The velocity (in m s⁻¹) at 2 s, before the given instant will be

1 6

2 4

3 2

4 1

Ans. (1) Here, u=10 m s-1, t=3 s, v=16 m s-1 a=v-ut=16-103=2 m s-2 Now velocity at 2 s, before the given instant, 10=u'+2×2 ∴ u'=6 m s-1 (∵ v=u+at)

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Q.
The velocity of a particle at an instant is 10 m $s ⁻ ¹$ . After 3 s, its velocity will become 16 m $s ⁻ ¹$ . The velocity (in m $s ⁻ ¹$ ) at 2 s, before the given instant will be

Ans.
(1)

Here, $u = 10 m s^{- 1}$ , $t = 3 s$ , $v = 16 m s^{- 1}$

$a = \frac{v - u}{t} = \frac{16 - 10}{3} = 2 m s^{- 2}$

Now velocity at $2 s$ , before the given instant,

$10 = u' + 2 \times 2$

$∴$ $u' = 6 m s^{- 1}$ $(∵ v = u + a t)$