The velocity – Distance graph is shown in figure. Which graph represents acceleration versus distance variation of this system? [2026]

Question

The velocity $(v)$ – Distance $(x)$ graph is shown in figure. Which graph represents acceleration $(a)$ versus distance $(x)$ variation of this system? [2026]

Smart Achievers · Accepted Answer

(2)

$Eq. of V vs x from graph$

$V = C_{1} - C_{2} x$

$a = V \frac{d V}{d x}$

$= (C_{1} - C_{2} x) \times (- C_{2})$

$a = C_{2}^{2} x - C_{1} C_{2}$

$∴$ $graph is straight line with positive slope and negative intercept$

Solution

Q.
The velocity $(v)$ – Distance $(x)$ graph is shown in figure. Which graph represents acceleration $(a)$ versus distance $(x)$ variation of this system [2026]

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2

3

4

Ans.
(2)

$Eq. of V vs x from graph$

$V = C_{1} - C_{2} x$

$a = V \frac{d V}{d x}$

$= (C_{1} - C_{2} x) \times (- C_{2})$

$a = C_{2}^{2} x - C_{1} C_{2}$

$∴$ $graph is straight line with positive slope and negative intercept$

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Solution

Q. The velocity (v) – Distance (x) graph is shown in figure. Which graph represents acceleration (a) versus distance (x) variation of this system [2026]

1

2

3

4

Ans. (2) Eq. of V vs x from graph V=C1-C2x a=VdVdx =(C1-C2x)×(-C2) a=C22x-C1C2 ∴ graph is straight line with positive slope and negative intercept

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Q.
The velocity $(v)$ – Distance $(x)$ graph is shown in figure. Which graph represents acceleration $(a)$ versus distance $(x)$ variation of this system [2026]

Ans.
(2)

$Eq. of V vs x from graph$

$V = C_{1} - C_{2} x$

$a = V \frac{d V}{d x}$

$= (C_{1} - C_{2} x) \times (- C_{2})$

$a = C_{2}^{2} x - C_{1} C_{2}$

$∴$ $graph is straight line with positive slope and negative intercept$