The variation of kinetic energy (KE) of a particle executing simple harmonic motion with the displacement , starting from mean position to extreme position , is given by [2023]

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Solution

Q.
The variation of kinetic energy (KE) of a particle executing simple harmonic motion with the displacement $(x)$ , starting from mean position to extreme position $(A)$ , is given by [2023]

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Ans.
(4)

$For a particle executing SHM$

$KE = \frac{1}{2} m ω^{2} (A^{2} - x^{2})$

$When x = 0, KE is maximum and when x = A, KE is zero, and the KE vs x graph is parabolic.$

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