The value of \theta\ for which 2{sin{\ }}^2\theta=\frac{1}{2},0^\circ\le\theta\le

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Solution

Q.
The value of $θ$ for which $2 {s i n}^{2} θ = \frac{1}{2}, 0 ° \leq θ \leq 90 ° i s$

1 $30 °$

2 $60 °$

3 $45 °$

4 $90 °$

Ans.
(2)

$2 {s i n}^{2} θ = \frac{1}{2} \Rightarrow {s i n}^{2} θ = \frac{1}{4} \Rightarrow s i n θ = \frac{1}{2} = s i n 30 ° \Rightarrow θ = 30 °$

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