The value of sin [ 2 sin - 1 ( 0 . 6 ) ] is:

Question

The value of $\sin [2 \sin^{- 1} (0.6)]$ is:

Smart Achievers · Accepted Answer

(2)

Ans. $\cdot 96$

Explanation:

Let $\sin^{- 1} (\cdot 6) = θ,$ i.e., $\sin θ = \cdot 6$

Now, $\sin [2 \sin^{- 1} (0.6)] = \sin (2 θ) = 2 \sin θ \cos θ$

$= 2 (\cdot 6) (\cdot 8) = \cdot 96$

$(∵ \cos θ = \sqrt{1 - \sin^{2} θ} = \sqrt{1 - {(0.6)}^{2}} = 0.8)$

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