The value of limn→∞(limx→0-∑r=12n+1[xr])+n+3ℓn(1+n)n-ℓn(n)n, where [·] denotes greatest integer function
(2)
limx→0-∑r=12n+1[xr]=limx→0-[x]+[x2]+[x3]+⋯+[x2n+1]
=(-1)+0+(-1)+⋯+0+(-1)=(-1)(n+1)=-n-1
⇒L=limn→∞-n-1+n+3nln(1+nn)
=limn→∞2(1n)ln(1+1n)⇒1n=t
⇒L=limt→02tln(1+t)=2