The value of electric potential at a distance of 9 cm from the point charge is [2024]

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Solution

Q.
The value of electric potential at a distance of 9 cm from the point charge $4 \times 10^{- 7} C$ is

$(Given that \frac{1}{4 π ε_{0}} = 9 \times 10^{9} {Nm}^{2} C^{- 2})$ [2024]

1 $4 \times 10^{2}$ $V$

2 $44.4$ $V$

3 $4.4 \times 10^{5}$ $V$

4 $4 \times 10^{4}$ $V$

Ans.
(4)

$r = 9$ $cm = 9 \times 10^{- 2}$ $m$

$q = 4 \times 10^{- 7}$ $C$

As, $V = \frac{1}{4 π ε_{0}} \frac{q}{r} = \frac{9 \times 10^{9} \times 4 \times 10^{- 7}}{9 \times 10^{- 2}} = 4 \times 10^{4}$ $V$

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