The unit of thermal cond

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Solution

Q.
The unit of thermal conductivity is [2019]

1 $W m^{- 1} K^{- 1}$

2 $J m {K^{- 1}}^{}$

3 $J m^{- 1} K^{- 1}$

4 $W m K^{- 1}$

Ans.
(1)

$K = \frac{Q}{A ({T_{1} - T_{2}) t}_{}}$ , where Q is the amount of heat flow, x is the thickness of the slab, A is the area of cross-section, and t is the time taken., $K = \frac{J m}{m^{2} K s} = W \frac{1}{m} \frac{1}{K} = W m^{- 1} {K^{- 1}}^{}$

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