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Solution


Q.

The terminal voltage of the battery, whose emf is 10 V and internal resistance 1Ω, when connected through an external resistance of 4Ω as shown in the figure is    [2024]
1 4 V  
2 6 V  
3 8 V  
4 10 V  

Ans.

(3)

Current in the given circuit

I=104+1=105=2A

Terminal voltage, V=E-Ir=10-2×1=8V