• 072920 77839
  • info@smartachievers.in
Menu
Back
  • JEE ADVANCE
  • JEE MAIN
  • NEET
  • BITSAT
  • CBSE BOARD
  • UP BOARD
  • CUET
JEE ADVANCE
  • CLASS XI - XII
  • CRASH COURSE
CRASH COURSE
JEE MAIN
  • CLASS XI - XII
  • CRASH COURSE
CRASH COURSE
NEET
  • CLASS XI - XII
  • CRASH COURSE
BITSAT
  • CLASS XI - XII
CBSE BOARD
  • CLASS IX
  • CLASS X
  • CLASS XI
  • CLASS XII
  • CLASS VI
  • CLASS VII
  • CLASS VIII
UP BOARD
  • CLASS IX
  • CLASS X
  • CLASS XI
  • CLASS XII
CUET
  • CRASH COURSE
Courses


Solution


Q.

The sum of the digits of a two-digit number is 9. If 27 is subtracted from the number, its digits are interchanged. Which of these is the product of the digits of the number
1 8  
2 14  
3 18  
4 20  

Ans.

(3)

Let x be the unit place digit and y be the ten’s place digit.

Two-digit number = 10y + x

According to the question,

x + y = 9 ...........(i)

10y + x – 27 = 10x + y ⇒ y – x = 3 ...........(ii)

Adding (i) and (ii), we get 2y = 9 + 3 ⇒ y = 6

Putting y = 6 in (i), we get x + 6 = 9 ⇒ x = 3

So, product of the digits of the number = 3 × 6 = 18