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Solution


Q.

The sum of the digits of a 2-digit number is 12. Seven times the number is equal to four times the number obtained by reversing the order of the digits. Find the number.

Ans.

(48)

Let the unit’s place digit be x and ten’s place digit be y

∴ Number = 10y+x

According to question,

x+y=12       ...(i)

and 7(10y+x)=4(10x+y)

x-2y=0    ...(ii)

Solving (i) and (ii), we get

x=8 and y=4

Hence, the required number is 48