The sum 1×1!+2×2!+...+50×50! equals
(2)
1(1!)+2(2!)+⋯+50(50!)
=(2-1)(1!)+(3-1)(2!)+(4-1)(3!)+⋯+(51-1)(50!)
=(2!-1!)+(3!-2!)+(4!-3!)+⋯+(51!-50!)
=51!-1!=51!-1