The steady state current in the circuit shown below is [2024]

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Solution

Q.
The steady state current in the circuit shown below is [2024]

1 0.67 A

2 1.5 A

3 2 A

4 1 A

Ans.
(3)

In steady state capacitor acts as an open circuit.

$R_{eq} = 2 + 3 = 5 Ω$

$V = 10 V$

$I = \frac{V}{R_{eq}} = \frac{10}{5} = 2$ $A$

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