The space between the plates of a parallel plate capacitor of capacitance C is filled with three dielectric slabs

Question

The space between the plates of a parallel plate capacitor of capacitance C is filled with three dielectric slabs of identical sizes as shown in figure. If the dielectric constants of the three slabs are $K_{1}, K_{2}$ and $K_{3}$ . Find the new capacitance.

Smart Achievers · Accepted Answer

(4)

$C = C_{1} + C_{2} + C_{3}$

Solution

Q.
The space between the plates of a parallel plate capacitor of capacitance C is filled with three dielectric slabs of identical sizes as shown in figure. If the dielectric constants of the three slabs are $K_{1}, K_{2}$ and $K_{3}$ . Find the new capacitance.

1 $\frac{C}{3} (K_{1} K_{2} + K_{2} K_{3} + K_{3} K_{1})$

2 $\frac{C}{3} (\frac{1}{K_{1}} + \frac{1}{K_{2}} + \frac{1}{K_{3}})$

3 $\frac{C}{3} (K_{1} K_{2} K_{3})$

4 $\frac{C}{3} (K_{1} + K_{2} + K_{3})$

Ans.
(4)

$C = C_{1} + C_{2} + C_{3}$

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Solution

Q. The space between the plates of a parallel plate capacitor of capacitance C is filled with three dielectric slabs of identical sizes as shown in figure. If the dielectric constants of the three slabs are K1,K2 and K3. Find the new capacitance.

1 C3(K1K2+K2K3+K3K1)

2 C3(1K1+1K2+1K3)

3 C3(K1K2K3)

4 C3(K1+K2+K3)

Ans. (4) C=C1+C2+C3