The shortest distance between the lines x - 5 1 = y - 2 2 = z - 4 - 3 and x + 3 1 = y + 5 4 = z - 1 - 5 is [2023]

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Solution

Q.
The shortest distance between the lines $\frac{x - 5}{1} = \frac{y - 2}{2} = \frac{z - 4}{- 3}$ and $\frac{x + 3}{1} = \frac{y + 5}{4} = \frac{z - 1}{- 5}$ is [2023]

1 $7 \sqrt{3}$

2 $6 \sqrt{3}$

3 $4 \sqrt{3}$

4 $5 \sqrt{3}$

Ans.
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