The resultant of two vectors and is perpendicular to and its magnitude is half that of . The angle between vectors and is

Question

The resultant of two vectors $\vec{A}$ and $\vec{B}$ is perpendicular to $\vec{A}$ and its magnitude is half that of $\vec{B}$ . The angle between vectors $\vec{A}$ and $\vec{B}$ is ____ . [2024]

Smart Achievers · Accepted Answer

(150)

$B \cos θ = \frac{B}{2} \Rightarrow θ = 60 °$

So, angle between $\vec{A}$ and $\vec{B}$ , $= 90 ° + 60 ° = 150 °$

Solution

Q.
The resultant of two vectors $\vec{A}$ and $\vec{B}$ is perpendicular to $\vec{A}$ and its magnitude is half that of $\vec{B}$ . The angle between vectors $\vec{A}$ and $\vec{B}$ is ____ . [2024]

Ans.
(150)

$B \cos θ = \frac{B}{2} \Rightarrow θ = 60 °$

So, angle between $\vec{A}$ and $\vec{B}$ , $= 90 ° + 60 ° = 150 °$

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Solution

Q. The resultant of two vectors A→ and B→ is perpendicular to A→ and its magnitude is half that of B→. The angle between vectors A→ and B→ is ____ . [2024]

Ans. (150) Bcosθ=B2⇒θ=60° So, angle between A→ and B→, =90°+60°=150°

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Q.
The resultant of two vectors $\vec{A}$ and $\vec{B}$ is perpendicular to $\vec{A}$ and its magnitude is half that of $\vec{B}$ . The angle between vectors $\vec{A}$ and $\vec{B}$ is ____ . [2024]

Ans.
(150)

$B \cos θ = \frac{B}{2} \Rightarrow θ = 60 °$

So, angle between $\vec{A}$ and $\vec{B}$ , $= 90 ° + 60 ° = 150 °$