The remainder when ( 32 32 ) 32 is divided by 7, is

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Solution

Q.
The remainder when ${(32^{32})}^{32}$ is divided by 7, is

1 2

2 4

3 6

4 5

Ans.
(2)

$We have, {(32^{32})}^{32} = 32^{1024} = {(28 + 4)}^{1024}$

$= 4 + a multiple of 28 = 4 + a multiple of 7$

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