The relationship between the magnetic susceptibility () and the magnetic permeability () is given by: ( is the permeability of free space and is relative permeability) [2025]

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Q.
The relationship between the magnetic susceptibility ( $χ$ ) and the magnetic permeability ( $μ$ ) is given by:

( $μ_{0}$ is the permeability of free space and $μ_{r}$ is relative permeability) [2025]

Solution

Q.
The relationship between the magnetic susceptibility ( $χ$ ) and the magnetic permeability ( $μ$ ) is given by:

( $μ_{0}$ is the permeability of free space and $μ_{r}$ is relative permeability) [2025]

1 $χ = \frac{μ}{μ_{0}} - 1$

2 $χ = \frac{μ_{r}}{μ_{0}} + 1$

3 $χ = μ_{T} + 1$

4 $χ = 1 - \frac{μ}{μ_{0}}$

Ans.
(1)

We have

$μ_{r} = (1 + χ) \Rightarrow χ = (μ_{r} - 1)$

$μ = μ_{0} μ_{r} \Rightarrow μ_{r} = \frac{μ}{μ_{0}}$

$∴ χ = (\frac{μ}{μ_{0}} - 1)$

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Solution

Q. The relationship between the magnetic susceptibility (χ) and the magnetic permeability (μ) is given by: (μ0 is the permeability of free space and μr is relative permeability) [2025]

1 χ=μμ0–1

2 χ=μrμ0+1

3 χ=μT+1

4 χ=1–μμ0

Ans. (1) We have μr=(1+χ) ⇒ χ=(μr–1) μ=μ0μr ⇒ μr=μμ0 ∴ χ=(μμ0–1)

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Q.
The relationship between the magnetic susceptibility ( $χ$ ) and the magnetic permeability ( $μ$ ) is given by:

( $μ_{0}$ is the permeability of free space and $μ_{r}$ is relative permeability) [2025]

1 $χ = \frac{μ}{μ_{0}} - 1$

2 $χ = \frac{μ_{r}}{μ_{0}} + 1$

3 $χ = μ_{T} + 1$

4 $χ = 1 - \frac{μ}{μ_{0}}$

Ans.
(1)

We have

$μ_{r} = (1 + χ) \Rightarrow χ = (μ_{r} - 1)$

$μ = μ_{0} μ_{r} \Rightarrow μ_{r} = \frac{μ}{μ_{0}}$

$∴ χ = (\frac{μ}{μ_{0}} - 1)$