The ratio of number of oxygen atoms to bromine atoms in the product Q is

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Solution

Q.

The ratio of number of oxygen atoms to bromine atoms in the product Q is _____ $\times 10^{- 1}$ . [2024]

Ans.
(15)

$= \frac{n_{o}}{n_{B r}} = \frac{3}{2} = 15 \times 10^{- 1}$

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