The quantum number of four electrons (e1, e2, e3, e4) are given below:

Question

Electron	$n$	$l$	$m$	$s$
e1	3	0	0	+1/2
e2	4	0	1	+1/2
e3	3	2	2	-1/2
e4	3	1	-1	+1/2

Decreasing energy of these electrons in multi-electron species:

Smart Achievers · Accepted Answer

(3)

$Energy \propto (n + l)$

$\begin{matrix} (n + l) \end{matrix}$ $[\begin{matrix} e_{3} & > & e_{2} & > & e_{4} & > & e_{1} \\ 3 + 2 & 4 + 0 & 3 + 1 & 3 + 0 \\ 5 & 4 & 4 & 3 \end{matrix}]$

Solution

Q.
The quantum number of four electrons (e1, e2, e3, e4) are given below:

Electron $n$ $l$ $m$ $s$

e1 3 0 0 +1/2

e2 4 0 1 +1/2

e3 3 2 2 -1/2

e4 3 1 -1 +1/2

Decreasing energy of these electrons in multi-electron species:

1 e4 > e3 > e2 > e1

2 e2 > e3 > e4 > e1

3 e3 > e2 > e4 > e1

4 e1 = e2 = e3 = e4

Ans.
(3)

$Energy \propto (n + l)$

$\begin{matrix} (n + l) \end{matrix}$ $[\begin{matrix} e_{3} & > & e_{2} & > & e_{4} & > & e_{1} \\ 3 + 2 & 4 + 0 & 3 + 1 & 3 + 0 \\ 5 & 4 & 4 & 3 \end{matrix}]$

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