The principal value of sin - 1 ( - 3 2 ) is:

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Solution

Q.
The principal value of $\sin^{- 1} (\frac{- \sqrt{3}}{2})$ is:

1 $- \frac{2 π}{3}$

2 $- \frac{π}{3}$

3 $\frac{4 π}{3}$

4 $\frac{5 π}{3}$

Ans.
(2)

Ans. $- \frac{π}{3}$

Explanation:

$\sin^{- 1} (\frac{- \sqrt{3}}{2}) = \sin^{- 1} (- \sin \frac{π}{3})$

$= - \sin^{- 1} (\sin \frac{π}{3}) = - \frac{π}{3}$

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