The principal value of sec - 1 ( - 2 3 ) is:

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Solution

Q.
The principal value of $\sec^{- 1} (\frac{- 2}{\sqrt{3}})$ is:

1 $\frac{5 π}{6}$

2 $\frac{2 π}{3}$

3 $\frac{π}{3}$

4 None of these

Ans.
(1)

Ans. $\frac{5 π}{6}$

Explanation:

$\sec^{- 1} (\frac{- 2}{\sqrt{3}}) = π - \sec^{- 1} (\frac{2}{\sqrt{3}})$

$= π - \frac{π}{6} = \frac{5 π}{6}$

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