Q.

The position of a particle is given by r→=3ti^+2t2j^+5k^, where t is in seconds and the coefficients have the proper units for r→ to be in metres. The direction of velocity of the particle at t = 1 s is

1 53° with x-axis  
2 37° with x-axis  
3 30° with y-axis  
4 60° with y-axis  

Ans.

(1)

Given : r→=3ti^+2t2j^+5k^

Velocity, v→=dr→dt=ddt(3ti^+2t2j^+5k^)=3i^+4tj^ m s-1

Let θ be the angle which the direction of v→ makes with the x-axis. Then

tanθ=vyvx=4t3=43 or  θ=tan-1(43)=53°