The perimeter of the sector of a circle of radius 21 cm which subtends an angle of 60° at the centre, is:
(3)
Let OAB be the given sector as shown in the figure.
Length of the corresponding arc,
AB=60°360°×2πr=16×2×227×21=22 cm⇒AB=22 cm∴Perimeter of the sector=OA+AB+BO=21+22+21=64 cm