The number of ways in which 5 boys and 3 girls can be seated on a round table if a particular boy and a particular girl never sit adjacent to each other, is

Question

The number of ways in which 5 boys and 3 girls can be seated on a round table if a particular boy $B_{1}$ and a particular girl $G_{1}$ never sit adjacent to each other, is

Smart Achievers · Accepted Answer

(2)

$Required number of ways = 7! - 6! \times 2$

$= 7 \times 6! - 6! \times 2 = 5 \times 6!$

Solution

Q.
The number of ways in which 5 boys and 3 girls can be seated on a round table if a particular boy $B_{1}$ and a particular girl $G_{1}$ never sit adjacent to each other, is

1 $7!$

2 $5 \times 6!$

3 $6 \times 6!$

4 $5 \times 7!$

Ans.
(2)

$Required number of ways = 7! - 6! \times 2$

$= 7 \times 6! - 6! \times 2 = 5 \times 6!$

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Solution

Q. The number of ways in which 5 boys and 3 girls can be seated on a round table if a particular boy B1 and a particular girl G1 never sit adjacent to each other, is

1 7!

2 5×6!

3 6×6!

4 5×7!

Ans. (2) Required number of ways=7!-6!×2 =7×6!-6!×2=5×6!