The number of ways, in which 16 oranges can be distributed to four children such that each child gets at least one orange, is [2026]
(3)
Let oranges be identical, then
x1+x2+x3+x4=16, and x1,x2,x3,x4≥1
or x1'+x2'+x3'+x4'=12
so total number of solutions are
=C312+3=C315=455