The number of solutions of the equation (9x–9x+2)(2x–7x+3)=0 is : [2025]
(3)
We have, (9x–9x+2)(2x–7x+3)=0 ... (i)
Put 1x=y in (i), we get
(9y2–9y+2)(2y2–7y+3)=0
⇒ (3y–2)(3y–1)(2y–1)(y–3)=0
⇒ y=23,13,12,3 ⇒ x=94,9,4,19
∴ Number of solutions = 4.