The number of distinct real values of 'K' such that the system of equations x+2y+z=1, x+3y+4z=K, x+5y+10z=K2 has infinitely many solutions is:
(3)
D=|1211341510|=0
D1=|121K34K2510|=5(K2-3K+2)=5(K-1)(K-2)
D2=|1111K41K210|=-3(K2-3K+2)=-3(K-2)(K-1)
D3=|12113K15K2|=K2-3K+2=(K-2)(K-1)