Q.

The number of distinct real values of 'K' such that the system of equations x+2y+z=1,  x+3y+4z=K,  x+5y+10z=K2 has infinitely many solutions is:

1 0  
2 4  
3 2  
4 3  

Ans.

(3)

D=|1211341510|=0

D1=|121K34K2510|=5(K2-3K+2)=5(K-1)(K-2)

D2=|1111K41K210|=-3(K2-3K+2)=-3(K-2)(K-1)

D3=|12113K15K2|=K2-3K+2=(K-2)(K-1)