The normal at a point P on the ellipse x2+4y2=16 meets the x-axis at Q. If M is the midpoint of the line segment PQ, then the locus of M intersects the latus rectums of the given ellipse at the points [2009]
(3)
Given ellipse is x242+y222=1
∴ a2=16, b2=4⇒e2=1-416=34⇒e=32
Let P(4cosθ, 2sinθ) be any point on the ellipse, then equation of normal at P is
4xsinθ-2ycosθ=12sinθcosθ
⇒x3cosθ-y6sinθ=1
∴ Q, the point where normal at P meets x-axis, has coordinates (3cosθ,0)
∴ Mid point of PQ is M(7cosθ2, sinθ)
For locus of point M we consider
x=7cosθ2, y=sinθ⇒cosθ=2x7, sinθ=y
Since sin2θ+cos2θ=1
∴ 4x249+y2=1 ...(i)
Also the latus rectum of given ellipse is
x=±ae=±4×32⇒x=±23 ...(ii)
On solving equations (i) and (ii), we get
4×1249+y2=1⇒y2=149 or y=±17
∴ The required points are (±23, ±17).