Q.

The normal at a point P on the ellipse x2+4y2=16 meets the x-axis at Q. If M is the midpoint of the line segment PQ, then the locus of M intersects the latus rectums of the given ellipse at the points              [2009]

1 (±352,±27)  
2 (±352,±194)  
3 (±23,±17)  
4 (±23,±437)  

Ans.

(3)

Given ellipse is x242+y222=1

  a2=16, b2=4e2=1-416=34e=32

Let P(4cosθ,2sinθ) be any point on the ellipse, then equation of normal at P is

4xsinθ-2ycosθ=12sinθcosθ

x3cosθ-y6sinθ=1

  Q, the point where normal at P meets x-axis, has coordinates (3cosθ,0)

  Mid point of PQ is M(7cosθ2,sinθ)

For locus of point M we consider

x=7cosθ2,  y=sinθcosθ=2x7,  sinθ=y

Since sin2θ+cos2θ=1

  4x249+y2=1    ...(i)

Also the latus rectum of given ellipse is

x=±ae=±4×32x=±23    ...(ii)

On solving equations (i) and (ii), we get

4×1249+y2=1y2=149 or y=±17

  The required points are (±23,±17).