The molar conductivity of a 0.5 solution of , with electrolytic conductivity of 5.76 at 298 K is [2016]

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Chemistry

Q.
The molar conductivity of a 0.5 $mol / {dm}^{3}$ solution of ${AgNO}_{3}$ , with electrolytic conductivity of 5.76 $\times 10^{- 3}$ $S$ ${cm}^{- 1}$ at 298 K is [2016]

1 2.88 S ${cm}^{2} / mol$

2 11.52 S ${cm}^{2} / mol$

3 0.086 S ${cm}^{2} / mol$

4 28.8 S ${cm}^{2} / mol$

Ans.
(2)

$Λ_{m} = \frac{κ \times 1000}{Molarity (M)}$

$= \frac{5.76 \times 10^{- 3} {S cm}^{- 1} \times 1000}{0.5 {mol cm}^{- 3}} = 11.52$ $S$ ${cm}^{2}$ ${mol}^{- 1}$

Solution

Q.
The molar conductivity of a 0.5 $mol / {dm}^{3}$ solution of ${AgNO}_{3}$ , with electrolytic conductivity of 5.76 $\times 10^{- 3}$ $S$ ${cm}^{- 1}$ at 298 K is [2016]

1 2.88 S ${cm}^{2} / mol$

2 11.52 S ${cm}^{2} / mol$

3 0.086 S ${cm}^{2} / mol$

4 28.8 S ${cm}^{2} / mol$

Ans.
(2)

$Λ_{m} = \frac{κ \times 1000}{Molarity (M)}$

$= \frac{5.76 \times 10^{- 3} {S cm}^{- 1} \times 1000}{0.5 {mol cm}^{- 3}} = 11.52$ $S$ ${cm}^{2}$ ${mol}^{- 1}$

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Solution

Q. The molar conductivity of a 0.5 mol/dm3 solution of AgNO3, with electrolytic conductivity of 5.76 ×10-3 S cm-1 at 298 K is [2016]

1 2.88 S cm2/mol

2 11.52 S cm2/mol

3 0.086 S cm2/mol

4 28.8 S cm2/mol

Ans. (2) Λm=κ×1000Molarity(M) =5.76×10-3 S cm-1×10000.5 mol cm-3=11.52 S cm2 mol-1

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Q.
The molar conductivity of a 0.5 $mol / {dm}^{3}$ solution of ${AgNO}_{3}$ , with electrolytic conductivity of 5.76 $\times 10^{- 3}$ $S$ ${cm}^{- 1}$ at 298 K is [2016]

1 2.88 S ${cm}^{2} / mol$

2 11.52 S ${cm}^{2} / mol$

3 0.086 S ${cm}^{2} / mol$

4 28.8 S ${cm}^{2} / mol$

Ans.
(2)

$Λ_{m} = \frac{κ \times 1000}{Molarity (M)}$

$= \frac{5.76 \times 10^{- 3} {S cm}^{- 1} \times 1000}{0.5 {mol cm}^{- 3}} = 11.52$ $S$ ${cm}^{2}$ ${mol}^{- 1}$