The maximum value of the expression 1sin2θ+3sinθcosθ+5cos2θ is _______. [2010]
(2)
Let f(θ)=1g(θ),
where g(θ)=sin2θ+3sinθcosθ+5cos2θ
Clearly f is maximum when g is minimum
Now g(θ)=1-cos2θ2+32sin2θ+52(1+cos2θ)
=3+2cos2θ+32sin2θ≥3+(-4+94)
∴ gmin=3-52=12⇒fmax=2