Q.

The maximum value of the expression 1sin2θ+3sinθcosθ+5cos2θ is _______.                      [2010]


Ans.

(2)

Let f(θ)=1g(θ),

where  g(θ)=sin2θ+3sinθcosθ+5cos2θ

Clearly f is maximum when g is minimum

Now g(θ)=1-cos2θ2+32sin2θ+52(1+cos2θ)

=3+2cos2θ+32sin2θ3+(-4+94)

 gmin=3-52=12fmax=2