The maximum number of electrons that can have principal quantum number, n=3 and spin quantum number ms=-1/2, is:

Question

The maximum number of electrons that can have principal quantum number, $n = 3$ and spin quantum number $m_{s} = - \frac{1}{2}$ , is:

Smart Achievers · Accepted Answer

(9)

With principal $' n'$ , the total number of electrons that can be present is given as $2 n^{2}$ .

$∴$ If $n = 3$ , total electrons can be $2 . 3^{2} = 18$ .

Out of them, half can have $m_{s} = - \frac{1}{2}$

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