The maximum intensity in a Young's double slit experiment is . Distance between the slits is , where is the wavelength of light used

Question

The maximum intensity in a Young's double slit experiment is $I_{0}$ . Distance between the slits $(d)$ is $5 λ$ , where $λ$ is the wavelength of light used. The intensity of the fringe, exactly opposite to one of the slits on the screen, placed at $D = 10 d$ is ______. [2026]

Smart Achievers · Accepted Answer

(2)

$Δ x_{p} = d \sin θ \approx d \tan θ = \frac{d y}{D} = \frac{d y}{10 d}$

$Δ x_{p} = \frac{y}{10} = \frac{2.5 λ}{10} = 0.25 λ$

$I = I_{0} \cos^{2} \frac{Δ ϕ}{2}$

$Δ ϕ = \frac{2 π}{λ} Δ x = \frac{2 π}{λ} \cdot 0.25 λ = 0.5 π = \frac{π}{2}$

$I_{p} = I_{0} \cos^{2} \frac{π}{4} = \frac{I_{0}}{2}$

Solution

Q.
The maximum intensity in a Young's double slit experiment is $I_{0}$ . Distance between the slits $(d)$ is $5 λ$ , where $λ$ is the wavelength of light used. The intensity of the fringe, exactly opposite to one of the slits on the screen, placed at $D = 10 d$ is ______. [2026]

1 $\frac{I_{0}}{4}$

2 $\frac{I_{0}}{2}$

3 $I_{0}$

4 $\frac{3 I_{0}}{4}$

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Solution

Q. The maximum intensity in a Young's double slit experiment is I0. Distance between the slits (d) is 5λ, where λ is the wavelength of light used. The intensity of the fringe, exactly opposite to one of the slits on the screen, placed at D=10d is ______. [2026]

1 I04

2 I02

3 I0

4 3I04