The magnetic field at the centre of a current carrying circular loop of radius R is 16 ?T . The magnetic field at a distance x = 3 R on its axis from the centre is______ T . [2026]

Question

The magnetic field at the centre of a current carrying circular loop of radius R is $16 μ T$ . The magnetic field at a distance $x = \sqrt{3} R$ on its axis from the centre is______ $μ T$ . [2026]

Smart Achievers · Accepted Answer

(1)

$\frac{μ_{0} I}{2 R} = 16 μ T$

$\frac{μ_{0} I R^{2}}{2 {(x^{2} + R^{2})}^{3 / 2}} = \frac{μ_{0} I R^{2}}{2 \times 8 R^{3}} = 2 μ T$

Solution

Q.
The magnetic field at the centre of a current carrying circular loop of radius R is $16 μ T$ . The magnetic field at a distance $x = \sqrt{3} R$ on its axis from the centre is______ $μ T$ . [2026]

1 2

2 $2 \sqrt{2}$

3 4

4 8

Ans.
(1)

$\frac{μ_{0} I}{2 R} = 16 μ T$

$\frac{μ_{0} I R^{2}}{2 {(x^{2} + R^{2})}^{3 / 2}} = \frac{μ_{0} I R^{2}}{2 \times 8 R^{3}} = 2 μ T$

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Solution

Q. The magnetic field at the centre of a current carrying circular loop of radius R is 16μT. The magnetic field at a distance x=3R on its axis from the centre is______μT. [2026]

1 2

2 22

3 4

4 8

Ans. (1) μ0I2R=16 μT μ0IR22(x2+R2)3/2=μ0IR22×8R3=2 μT

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Q.
The magnetic field at the centre of a current carrying circular loop of radius R is $16 μ T$ . The magnetic field at a distance $x = \sqrt{3} R$ on its axis from the centre is______ $μ T$ . [2026]

2 $2 \sqrt{2}$

Ans.
(1)

$\frac{μ_{0} I}{2 R} = 16 μ T$

$\frac{μ_{0} I R^{2}}{2 {(x^{2} + R^{2})}^{3 / 2}} = \frac{μ_{0} I R^{2}}{2 \times 8 R^{3}} = 2 μ T$