The line passing through the point of intersection of x+y=2, x-y=0 and is parallel to x+2y=5 is ax+by=c, then value of a+b+c is _________.
(6)
Required equation of line which is parallel to given line x+2y=5 is x+2y+k=0 …(i)
Given equations of lines are
x+y=2 …(ii)
x-y=0 …(iii)
Adding (ii) and (iii), we get 2x=2⇒x=1
Substituting x=1 in (iii), we get y=1
∴ Point of intersection is (1,1)
Substituting x=1, y=1 in (i), we get
1+2+k=0⇒k=-3
∴ Required equation of line is x+2y=3
Here, a=1, b=2 and c=3
∴ a+b+c=1+2+3=6