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Solution


Q.

The largest number that will divide 398, 436 and 542 leaving remainders 7, 11 and 15 respectively is
1 17  
2 11  
3 34  
4 45  

Ans.

(1)

Explanation: Algorithm 398 - 7 = 391; 436 - 11 = 425; 542 - 15 = 527

∴ HCF of 391, 425, 527 = 17