The interval on which the function f(x)=2x3+9x2+12x-1 is decreasing is:
(2)
Ans. [-2,-1]
Explanation:
We have, f(x)=2x3+9x2+12x-1
∴ f'(x)=6x2+18x+12
=6(x2+3x+2)=6(x+2)(x+1)
So, f'(x)≤0, for decreasing.
On drawing the number line as below:
We see that f'(x) is decreasing in [-2,-1].