Q.

The interval on which the function f(x)=2x3+9x2+12x-1 is decreasing is: 

1 [-1,∞)  
2 [-2,-1]  
3 (-∞,-2]  
4 [-1,1]  

Ans.

(2)

Ans.       [-2,-1]

Explanation:

We have,         f(x)=2x3+9x2+12x-1

∴                f'(x)=6x2+18x+12

                                =6(x2+3x+2)=6(x+2)(x+1)

So,  f'(x)≤0, for decreasing.

On drawing the number line as below:

We see that f'(x) is decreasing in [-2,-1].