The increase in the pressure required to decrease the volume of water is . The percentage decrease in the volume is

Question

The increase in the pressure required to decrease the volume $(Δ V)$ of water is $6.3 \times 10^{7} {N/m}^{2}$ . The percentage decrease in the volume is ______.

(Bulk modulus of water = $2.1 \times 10^{9} N / m^{2}$ ) [2026]

Smart Achievers · Accepted Answer

(2)

$Bulk modulus β = \frac{- Δ P}{(\frac{Δ V}{V})}$

$2.1 \times 10^{9} N / m^{2}$

$Percentage decrease = 3 %$

Solution

Q.
The increase in the pressure required to decrease the volume $(Δ V)$ of water is $6.3 \times 10^{7} {N/m}^{2}$ . The percentage decrease in the volume is ______.

(Bulk modulus of water = $2.1 \times 10^{9} N / m^{2}$ ) [2026]

1 2%

2 3%

3 6%

4 4%

Ans.
(2)

$Bulk modulus β = \frac{- Δ P}{(\frac{Δ V}{V})}$

$100 \times \frac{Δ V}{V} = \frac{- Δ P}{β} \times 100 = \frac{- 6.3 \times 10^{7}}{2.1 \times 10^{9}} \times 100 = - 3 %$

$Percentage decrease = 3 %$

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