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Solution


Q.

The incorrect statement regarding the given structure is:                          [2024]
1 has 4-asymmetric carbon atom  
2 will coexist in equilibrium with 2 other cyclic structures  
3 can be oxidized to a dicarboxylic acid with Br2 water  
4 despite the presence of –CHO does not give Schiff’s test  

Ans.

(3)

1.    

2.    Two cyclic forms of glucose exist in equilibrium with its open chain structure.

3.    Bromine water is a mild oxidizing agent, it oxidizes easily oxidisable aldehyde group to carboxylic acid, but cannot oxidize alcoholic group.

4.    Despite having the presence of –CHO group, glucose does not give Schiff’s test because under the reaction conditions, it exists as cyclic form and free –CHO group is thus not available.