The given figure represents two isobaric processes for the same mass of an ideal gas, then

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Solution

Q.
The given figure represents two isobaric processes for the same mass of an ideal gas, then [2024]

1 $P_{1} > P_{2}$

2 $P_{2} > P_{1}$

3 $P_{1} = P_{2}$

4 $P_{2} < P_{1}$

Ans.
(1)

$P V = n R T \Rightarrow V = (\frac{n R}{P}) T$

$Slope = \frac{n R}{P} \Rightarrow Slope \propto \frac{1}{P}$

${(Slope)}_{2} > {(Slope)}_{1} \Rightarrow P_{2} < P_{1}$

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