Q.

The function f(x)=cot x is discontinuous on the set:

1 {x=nπ:n∈Z}  
2 {x=2nπ:n∈Z}  
3 {x=(2n+1)π2:n∈Z}  
4 {x=nπ2:n∈Z}  

Ans.

(1)

Ans.    {x=nπ:n∈Z}

Explanation:

We know that, f(x)=cotx is continuous in R-{nπ:n∈Z}

Since, f(x)=cotx=cosxsinx                [Since, sinx=0 at nπ, n∈Z]

Hence, f(x)=cotx is discontinuous on the set {x=nπ:n∈Z}