The function f(x)=2x3-3x2-12x+4, has:
(3)
Ans. One maxima and one minima
Explanation:
We have, f(x)=2x3-3x2-12x+4
∴ f'(x)=6x2-6x-12
Now, f'(x)=0
⇒ 6(x2-x-2)=0
⇒ 6(x+1)(x-2)=0
⇒ x=-1 and x=2
On the number line for f'(x), we get
Hence, x=-1 is the point of local maxima and x=2 is the point of local minima.
So, f(x) has one maxima and one minima.