The expression tanA1-cotA+cotA1-tanA can be written as: [2013]
(2)
Given expression can be written as
sinAcosA×sinAsinA-cosA+cosAsinA×cosAcosA-sinA
=1sinA-cosA{sin3A-cos3AcosAsinA}
∵ a3-b3=(a-b)(a2+ab+b2)
=sin2A+sinAcosA+cos2AsinAcosA=1+secAcosecA