The equations of the lines through the point (3, 2) which makes an angle of 45° with the line x-2y=3 are
(1)
Let the slope of the required line be m.
∴ y-2x-3=m ...(i)
Given line is x-2y=3⇒y=12x-32 ...(ii)
Clearly, slope of the line is 12
It is given that the angle between (i) and (ii) is 45°
∴ |m-121+12m|=tan45°⇒2m-12+m=1 or 2m-12+m=-1
⇒ m=3 or m=-13
∴ Required equation is y-2x-3=3 or y-2x-3=-13
i.e., 3x-y-7=0 or x+3y-9=0.