Q.

The equation of the directrix of the parabola y2+4y+4x+2=0 is                      [2001]

1 x=-1    
2 x=1    
3 x=-32    
4 x=32    

Ans.

(4)

Given equation of the parabola is y2+4y+4x+2=0

y2+4y+4=-4x+2(y+2)2=-4(x-12)

It is of the form Y2=-4AX

Equation of whose directrix is given by X=A

 Equation of required directrix is x-12=1x=32