The equation of a straight line which is parallel to x - 2y + 8 = 0 and passes through (0, 4) is:

Question

The equation of a straight line which is parallel to $x - 2 y + 8 = 0$ and passes through (0, 4) is:

Smart Achievers · Accepted Answer

(1)

$The equation of a line parallel to the line x - 2 y + 8 = 0$ $is$ $x - 2 y + λ = 0$ ...(i)

$This passes through$ $(0, 4)$

$∴$ $0 - 2 (4) + λ = 0 \Rightarrow λ = 8$

$Putting$ $λ = 8$ $in (i), we get$

$x - 2 y + 8 = 0,$ which is the required equation.

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