The energy of ion in its first excited state is. (The ground state energy for the Hydrogen atom is ?13.6 eV) [2023]

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Solution

Q.
The energy of ${He}^{+}$ ion in its first excited state is. [2023]

(The ground state energy for the Hydrogen atom is −13.6 eV)

1 −3.4 eV

2 −54.4 eV

3 −13.6 eV

4 −27.2 eV

Ans.
(3)

$E_{a} = \frac{- 13.6 Z^{2}}{n^{2}} = \frac{- 13.6 \times 4}{4} = - 13.6 eV$

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