The electrostatic force between the metal plates of an isolated parallel plate capacitor C having a charge Q and area A, is [2018]

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Q.
The electrostatic force between the metal plates of an isolated parallel plate capacitor C having a charge Q and area A, is [2018]

1 independent of the distance between the plates

2 linearly proportional to the distance between the plates

3 proportional to the square root of the distance between the plates

4 inversely proportional to the distance between the plates.

Ans.
(1)

Electrostatic force,

$F_{plate} = Q E = Q \times \frac{Q}{2 ε_{0} A} = \frac{Q^{2}}{2 A ε_{0}}$

$F$ is independent of the distance between plates.

Solution

Q.
The electrostatic force between the metal plates of an isolated parallel plate capacitor C having a charge Q and area A, is [2018]

1 independent of the distance between the plates

2 linearly proportional to the distance between the plates

3 proportional to the square root of the distance between the plates

4 inversely proportional to the distance between the plates.

Ans.
(1)

Electrostatic force,

$F_{plate} = Q E = Q \times \frac{Q}{2 ε_{0} A} = \frac{Q^{2}}{2 A ε_{0}}$

$F$ is independent of the distance between plates.

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Solution

Q. The electrostatic force between the metal plates of an isolated parallel plate capacitor C having a charge Q and area A, is [2018]

1 independent of the distance between the plates

2 linearly proportional to the distance between the plates

3 proportional to the square root of the distance between the plates

4 inversely proportional to the distance between the plates.

Ans. (1) Electrostatic force, Fplate=QE=Q×Q2ε0A=Q22Aε0 F is independent of the distance between plates.

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Q.
The electrostatic force between the metal plates of an isolated parallel plate capacitor C having a charge Q and area A, is [2018]

Ans.
(1)

Electrostatic force,

$F_{plate} = Q E = Q \times \frac{Q}{2 ε_{0} A} = \frac{Q^{2}}{2 A ε_{0}}$

$F$ is independent of the distance between plates.