The electron concentration in an -type semiconductor is the same as hole concentration in a -type semiconductor. An external field (electric) is applied across each of them. Compare the currents in them. [2021]

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Q.
The electron concentration in an $n$ -type semiconductor is the same as hole concentration in a $p$ -type semiconductor. An external field (electric) is applied across each of them. Compare the currents in them. [2021]

1 No current will flow in $p$ -type, current will only flow in $n$ -type.

2 Current in $n$ -type = current in $p$ -type.

3 Current in $p$ -type > current in $n$ -type.

4 Current in $n$ -type > current in $p$ -type.

Ans.
(4)

Mobility of electrons is more as compare to holes and electrons are majority charge carriers in $n$ -type semiconductors. So when we apply electric field, current will be more in $n$ -type semiconductor compare to $p$ -type semiconductor.

Solution

Q.
The electron concentration in an $n$ -type semiconductor is the same as hole concentration in a $p$ -type semiconductor. An external field (electric) is applied across each of them. Compare the currents in them. [2021]

1 No current will flow in $p$ -type, current will only flow in $n$ -type.

2 Current in $n$ -type = current in $p$ -type.

3 Current in $p$ -type > current in $n$ -type.

4 Current in $n$ -type > current in $p$ -type.

Ans.
(4)

Mobility of electrons is more as compare to holes and electrons are majority charge carriers in $n$ -type semiconductors. So when we apply electric field, current will be more in $n$ -type semiconductor compare to $p$ -type semiconductor.

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Solution

Q. The electron concentration in an n-type semiconductor is the same as hole concentration in a p-type semiconductor. An external field (electric) is applied across each of them. Compare the currents in them. [2021]

1 No current will flow in p-type, current will only flow in n-type.

2 Current in n-type = current in p-type.

3 Current in p-type > current in n-type.

4 Current in n-type > current in p-type.

Ans. (4) Mobility of electrons is more as compare to holes and electrons are majority charge carriers in n-type semiconductors. So when we apply electric field, current will be more in n-type semiconductor compare to p-type semiconductor.

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Q.
The electron concentration in an $n$ -type semiconductor is the same as hole concentration in a $p$ -type semiconductor. An external field (electric) is applied across each of them. Compare the currents in them. [2021]

1 No current will flow in $p$ -type, current will only flow in $n$ -type.

2 Current in $n$ -type = current in $p$ -type.

3 Current in $p$ -type > current in $n$ -type.

4 Current in $n$ -type > current in $p$ -type.

Ans.
(4)

Mobility of electrons is more as compare to holes and electrons are majority charge carriers in $n$ -type semiconductors. So when we apply electric field, current will be more in $n$ -type semiconductor compare to $p$ -type semiconductor.