Q.

The domain of f(x) is (0, 1), therefore, the domain of y=f(ex)+f(ln|x|) is:

1 (1e,1)  
2 (-e,-1)  
3 (-1,-1e)  
4 (-e,-1)∪(1,e)  

Ans.

(2)

y=f(ex)+f(ln|x|)

domain f(x)=(0,1)⇒0<ex<1⇒x<0    ……(1)

and 0<ln|x|<1⇒1<|x|<e⇒x∈(-e,-1)∪(1,e)    ……(2)

Taking intersection x∈(-e,-1)